Homework.lv - Arhīvs - Algebra, 12. klase, lpp. 5

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Uzraksti mums

Atbilžu arhīvs

№ 24610, Algebra, 12 klase
cosx=1-sinx

vespertilio

cosx+sinx=1
(cosx+sinx)²=1
cos²x+2sinxcosx+sin²x=1
sinxcosx=0
sinx=0 vai cosx=0
x=0,5*pi*n, n vesels skaitlis
x=0,5*pi+pi*n

arieta

faila

1/1

№ 24649, Algebra, 12 klase
rewite pozalujsta.. eto vse v sistemah
c) cos x cos y = √3/4
sin x sin y = √3/4

F) cos(x-y)= 1
cos(x+y)= -½

j) sin x sin y = ¾
cos x cos y = ¼

arieta

Решение см. в файле

1/1

№ 24755, Algebra, 12 klase
1.Aprēķināt izteiksmes skiatlisko vērtību.
a) (1470:21:7:20) + (1470 : ((21:7) · 20));
b) (336:7+5-4) + (336:(7+5)-4) - (336:(7+(5-4)));
c) | (-35-47) : 41 | -15+ | (48-59) · (-3) -55|;
d) | -64:4 - 42:3 | + | -120: (-4) | +15 · (-4);
2.
a) (5/8 ( piecas astotās..) - 0, 85) · 0,4 - 0,318:0,3;
b) (2/5 - 1,22) : 0,4 + 4/5 · 4;
c) 0,1 · 0,95 - 0,275) : 0,9 - 1/10;
d) -0,856:0,8+0,6 · (0,025 - 3/40)
e) -7,56:0,7+1,2 · (0,35 - 3/5)

Paldies par atsaucību..!

agija

1.)a) =0,5+24,5=25
b)=49+24-42=31
c)
d)
2.)a)0,285-1,6=-1,315
b)-2,65+3,2=0,55
c)-0,2-0,1=-0,3
d)-1,07-0,03=-1,1
e)-10,8-0,37=-11,17

Bonny

1.uzdevums
a) = (70:7:20)+(1470:(3*20))=
=(10:20)+(1470:60)=
=1/2(viena otrā)+24.5=
=0.5+24.5=25
b) =(48+5-4)+(336:12-4)-(336:(7+1))=
=(53-4)+(28-4)-(336:8)=
=49+24-42=
=73-42=31
c) un d) neatceros kā pildīja moduļus
2. uzdevums
a) =(5/8(pareizina ar 125)-85/100(pareizina ar 10))*0.4-1.06=
=(0.625-0.850)*0.4-1.06=
=-0.225*0.4-1.06=
=-0.09-1.06=1.15
b) =(0.40(divas piektās pareizināju ar 40)-1.22):0.4+18=
=-0.82:0.4+18=
=-2.05+18=15.95
c) =(0.095+0.275):0.9-1/10=
=0.18:0.9-1/10=
=0.2-1/10=
=0.2-0.1=0.1
d) =-1.07+0.6*(25/1000-3/40)=
=-1.07+0.6*(1/40-3/40)=
=-1.07+0.6*2/40=
=-1.07+0.6*1/20=
=-1.07+0.6*0.5=
=-1.07+0.3=-0.77
e) =-10.8+1.2*(35/100-60/100)=
=-10.8+1.2*(-25/100)=
=-10.8+1.2*(-0.25)=
=-10.8-0.3=11.10

1/2

bavarde

1.a)(1470:21:7:20)+(1470:((21:7)·20))=0.5+(1470:(3·20))=0.5+(1470:60)=0.5+24.5=25
b)(336:7+5-4)+(336:(7+5)-4)-(336:(7+(5-4)))=(48+1)+(336:12-4)-(336:(7+1))= 49+(28-4)-(336:8)=49+24-42=31
c)|(-35-47):41|-15+|(48-59)·(-3)-55|=|(-82):41|-15+|(-11)·(-3)-55|=|-2|-15+|33-55|= 2-15+|-22|=-13+22=9
d)|-64:4-42:3|+|-120:(-4)|+15·(-4)=|-6-14|+|30|-60=|-20|+30-60=20-30=-10
2.a)(5/8-0,85)·0,4-0,318:0,3=(0.625-0.85)·0.4-1.06=-0.225·0.4-1.06=-0.09-1.06=-1.15
b)(2/5-1,22):0,4+4/5·4=(0.4-1.22):0.4+0.8·4=-0.82:0.4+3.2=-2.05+3.2=1.15
c)(0,1·0,95-0,275):0,9-1/10=(0.095-0.275):0.9-0.1=-0.18:0.9-0.1=-0.2-0.1=-0.3

Tas

Atrisinājums peilikuma

1/2

№ 24782, Algebra, 12 klase
(cos²a-sin²a)²=cos2a

Tas

Ar visu zīmējumu

1/1

№ 24822, Algebra, 12 klase
2*(lgx)kvadrata+(1-√2)lgx²=2√2

arieta

failaa

1/1

№ 24823, Algebra, 12 klase
y=zem kvadratsaknes(x²-25) + lg(42+x-x²)

arieta

fail

1/1

№ 24824, Algebra, 12 klase
(log pie bazes 5 no x)²+1/2log pie bazes 5 no 5x -2 = 0

bavarde

(log pie bazes 5 no x)²+½log pie bazes 5 no 5x -2=0
(log pie bazes 5 no x)²+½(log pie bazes 5 no 5 + log pie bazes 5 no x) -2=0
(log pie bazes 5 no x)²+½(1 + log pie bazes 5 no x) -2=0
(log pie bazes 5 no x)²+½+½log pie bazes 5 no x -2=0
(log pie bazes 5 no x)²+½log pie bazes 5 no x-1½=0
log pie bazes 5 no x=a (apzīmēsim)
a²+½a-1½=0
2a²+a-3=0
D=1-4*2*(-3)=1+24=25
√D=√25=5
a1=(-1+5)/4=4/4=1 a2=(-1-5)/4=-6/4=-1.5
log pie bazes 5 no x=1 log pie bazes 5 no x=-1.5
x=5 x=1/(³√25)

arieta

failaa

1/1

№ 24825, Algebra, 12 klase
log pie bazes 2 no x* log pie bazes 2 no x/4 + log pie bazes 2 no x³ -2=0

bavarde

(log pie bazes 2 no x)*(log pie bazes 2 no x/4)+(log pie bazes 2 no x³) -2=0
(log pie bazes 2 no x)*(log pie bazes 2 no x - log pie bazes 2 no 4)+(log pie bazes 2 no x³) -2=0
(log pie bazes 2 no x)*(log pie bazes 2 no x - 2)+3(log pie bazes 2 no x) -2=0
(log pie bazes 2 no x)²-2(log pie bazes 2 no x)+3(log pie bazes 2 no x) -2=0
(log pie bazes 2 no x)²+(log pie bazes 2 no x)-2=0
log pie bazes 2 no x=a (apzīmēsim)
a²+a-2=0
a1=-2 a2=1
log pie bazes 2 no x=-2 log pie bazes 2 no x=1
x=¼ x=2

vespertilio

skat. failu.

1/1

№ 25426, Algebra, 12 klase Dots: lg3=a; lg5=b Izteikt: lg45 = ?

	M	lg45=3lgab

	robis	lg45=3ab

	angel	lg45=lg3+lg3+lg5=a+a+b=2a+b

	bavarde	lg45=lg(533)=lg5+lg3+lg3=b+a+a=2a+b

	elizabete	lg45=2lg3+lg5=lg3^2(2 ir pakape!)+lg5=lg3^25=a^2b