![Atbilžu arhīvs](/images/wnd_title_pic_3.gif) | Atbilžu arhīvs | № 24071, Algebra, 8 klase x+y=5 x-y=7 | | |
| | ![Ozo](/profiles/defined_pic_1.gif)
![Ozo](/images/sch_level_sml_0.gif) Ozo | Atbilde sk. faila | | |
| | ![liliana4](/profiles/upic_5378.jpg)
![liliana4](/images/sch_level_sml_0.gif) liliana4 | x+y=5 x-y=7 --------- 2x=12 x=12÷2 x=6
6+y=5 y= -1 Atbilde: (6, -1) | | |
| | ![city](/profiles/defined_pic_2.gif)
![city](/images/sch_level_sml_0.gif) city | x+x=5+7 2x=12 x=6 | | |
| | ![eke](/profiles/upic_5171.jpg)
![eke](/images/sch_level_sml_0.gif) eke | (x+y)+(x-y)=5+7 x+y+x-y=12 2x=12 x=12:2 x=6
6+y=5 y=5-6 y=-1 | | |
| | ![Markoo](/profiles/defined_pic_4.gif)
![Markoo](/images/sch_level_sml_0.gif) Markoo | x+y=5 x-y=7
7+y+y=5 x=7+y
2y=-2 x=7+y
y=-1 x=7-1
y=-1 x=6
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| | № 24074, Algebra, 8 klase 3x+4y=14 x+5y=12 | | |
| | ![liliana4](/profiles/upic_5378.jpg)
![liliana4](/images/sch_level_sml_0.gif) liliana4 | 3x+4y=14 x+5y=12 ·(-3) _______ 3x+4y=14 -3x -15y=-36 _______ -11y=-22 y=2 3x=-8+14 3x=6 x=2 Atbilde: (2, 2) | | |
| | ![kašķīte](/profiles/defined_pic_2.gif)
![kašķīte](/images/sch_level_sml_0.gif) kašķīte | 3x+4y=14 x+5y=12
x=12-5y
3*(12-5y) +4y=14 36-15y+4y-14=0 -11y=-22 y=2
x=12-5y x=12-5*2 x=12-10 x=2 | | |
| | ![angel](/profiles/upic_3914.jpg)
![angel](/images/sch_level_sml_2.gif) angel | x=12-5y
3(12-5y)+4y=14 36-15y+4y=14 11y=36-14 11y=22 y=2
x=12-5y x=12-5·2=12-10=2 | | |
| | ![spooky](/profiles/upic_4048.jpg)
![spooky](/images/sch_level_sml_0.gif) spooky | 3x+4y=14 x+5y=12 | -3
3x+4y=14 -3x -15y=-36
-11y=-22 y=2
3x+4*2=14 3x+8=14 3x=6 x=2 | | |
| | ![malinka678](/profiles/defined_pic_2.gif)
![malinka678](/images/sch_level_sml_0.gif) malinka678 | 3x+ 4y=14 x+5y =12 /*3 3x+4y = 14 -3x-15y = - 36 -11y=-22 y= 2 3x+8=14 3x=6 x=2 | |
| № 24081, Algebra, 8 klase atrisini vienadojumus:
a)(y+7)(y-7)+48=0 b)(2-k)(k+1)=k c)(3x-1)²+6x=1 | | |
| | ![missL](/profiles/upic_5348.jpg)
![missL](/images/sch_level_sml_0.gif) missL | a)(y+7)(y-7)+48=0 y²-49+48=0 y²=1 y = 1 y = -1 b)(2-k)(k+1)=k 2k + 2 - k² -k = k k² = 2 c)(3x-1)²+6x=1 9x² -6x + 1 + 6x = 1 9x² = 0 x² = 0 | | |
| | ![liliana4](/profiles/upic_5378.jpg)
![liliana4](/images/sch_level_sml_0.gif) liliana4 | a) (y+7)(y-7)+48=0 y²-49+48=0 y²=49-48 y²=1 b)(2-k)(k+1)=k 2k+2-k²-k=k
c)(3x-1)²+6x=1 9x²-8x+1+6x=1 9x²-2x=1-1 9x²-2x=0 | | |
| | ![Zjuzja](/profiles/defined_pic_2.gif)
![Zjuzja](/images/sch_level_sml_0.gif) Zjuzja | a) (y+7)(y-7)+48=0 y²-49+48=0 y²-1=0 y=1 b) (2-k)(k+1)=k 2k+2-k²-k-k=k 2-k²=0 -k²= -2 k²=2 k= 2 3) (3x-1)²+6x=1 (3x-1)(3x-1) + 6x =1 9x² - 6x + 1 + 6x =1 9x² = 1-1 9x²=0 x=0 | | |
| | ![jolitis](/profiles/defined_pic_4.gif)
![jolitis](/images/sch_level_sml_0.gif) jolitis | a) (y+7)(y-7)+48=0 y²-7y+7y-49+48=+/-1 b) (2-k)(k+1)=k 2k+2-k²-k=+/-√2 c) (3x-1)²+6x=1 3x²-2*3x*(-1)+6x-1=0 3x²+12x-1=0 x1=0 ; x2=-1 | | |
| | ![malinka678](/profiles/defined_pic_2.gif)
![malinka678](/images/sch_level_sml_0.gif) malinka678 | A) (y+7)(y-7) + 48=0 y2-49=48=0 y2-1=0 y=1
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| № 24084, Algebra, 8 klase √24:2 | | |
| | ![caca](/profiles/defined_pic_2.gif)
![caca](/images/sch_level_sml_0.gif) caca | √24 =4.8 4.8÷2=2.4 atbilde:2.4 | | |
| | ![Aniuta](/profiles/upic_5317.jpg)
![Aniuta](/images/sch_level_sml_0.gif) Aniuta | √24÷2 = √12 = √3·4=2√3 | | |
| | ![malinka678](/profiles/defined_pic_2.gif)
![malinka678](/images/sch_level_sml_0.gif) malinka678 | / (korenj) /24: 2 2/6:2= 1/3
| | |
| | ![spooky](/profiles/upic_4048.jpg)
![spooky](/images/sch_level_sml_0.gif) spooky | √24:2=√4*6 :2 = 6√4 :2=6√2 :2=3√2 | | |
| | ![angel](/profiles/upic_3914.jpg)
![angel](/images/sch_level_sml_2.gif) angel | √24÷2=√(4·6)÷2=2√6÷2=√6 | |
| № 24087, Algebra, 8 klase 4z-6=0
| | |
| | ![Archa4](/profiles/defined_pic_1.gif)
![Archa4](/images/sch_level_sml_0.gif) Archa4 | 4z-6=0 4z=6 z=4/6 z=1,5 | | |
| | ![angel](/profiles/upic_3914.jpg)
![angel](/images/sch_level_sml_2.gif) angel | 4z=6 z=6÷4=1,5 | | |
| | ![kostja](/profiles/upic_3447.jpg)
![kostja](/images/sch_level_sml_0.gif) kostja | 4z-6=0 4z=6 z=6÷4 z=1.5 | | |
| | ![param pam pam](/profiles/upic_4783.jpg)
![param pam pam](/images/sch_level_sml_0.gif) param pam pam | 4z=6 z=6÷4 z=1,5 | | |
| | ![spooky](/profiles/upic_4048.jpg)
![spooky](/images/sch_level_sml_0.gif) spooky | 4z-6=0 4z=6 z=6/4 z=1,5 | |
| | № 24090, Algebra, 8 klase Решите уравнения: 1) x²-7x=0 2) 4m-m²=0 3) -2y²+3y=0 4) x-5x²=0 5) 0,5x²+1,2x=0 | | |
| | ![Игорь](/profiles/defined_pic_4.gif)
![Игорь](/images/sch_level_sml_0.gif) Игорь | 1) x²-7x=0 x=0 x=7 2) 4m-m²=0 m=0 m=4 3) -2y²+3y=0 y=0 y=1,5 4) x-5x²=0 x=0 x=0,2 5) 0,5x²+1,2x=0 x=0 x=2,4 | | |
| | ![Senja](/profiles/defined_pic_4.gif)
![Senja](/images/sch_level_sml_0.gif) Senja | 1) x²-7x=0 2) 4m-m²=0 3) -2y²+3y=0 4) x-5x²=0 x(x-7)=0 m(4-m)=0 y(-2y+3)=0 x(1-5x)=0 x=0 или x=7 m=0 или m=4 y=0 или y=1.5 x=0 или x=0.2
5) 0.5x²+1.2x=0 x(0.5x+1.2)=0 x=0 или x=-2.4 | | |
| | ![Katy](/profiles/upic_5285.jpg)
![Katy](/images/sch_level_sml_0.gif) Katy | 1) x²-7x=0 x(x-7)=0 x=0 vai x-7=0 x=7 Atbilde:{0;7}
2) 4m-m²=0 m(4-m)=0 m=0 vai 4-m=0 m=4 Atbilde:{0;4}
3) -2y²+3y=0 -y(2y-3)=0 y=0 vai 2y=3 y=1,5 Atbilde{0;1,5}
4) x-5x²=0 x(1-5x)=0 x=0 vai 1-5x=0 5x=1 x=0,2 Atbilde:{0;0,2}
5) 0,5x²+1,2x=0 0,5x(x+2,4)=0 0,5x=0 vai x+2,4=0 x=0 x=-2,4 Atbilde{0;2,4} | | |
| | ![kašķīte](/profiles/defined_pic_2.gif)
![kašķīte](/images/sch_level_sml_0.gif) kašķīte | 1) x²-7x=0 x(x-7)=0 x=0 vau x-7=0 --> x=7
2) 4m-m²=0 m(4-m)=0 m=0 vai 4-m=0--> m=4
3) -2y²+3y=0 y(-2y+3)=0 y=0 vai -2y+3=0--> y=3/2
4) x-5x²=0 x(1-5x)=0 x=0 vai 1-5x=0---> x=1/5
5) 0,5x²+1,2x=0 x(0.5x+1.2)=0 x=0 vai 0.5x+1.2=0---> x=-2.4 | | |
| | ![Zjuzja](/profiles/defined_pic_2.gif)
![Zjuzja](/images/sch_level_sml_0.gif) Zjuzja | 1) x²-7x=0 x(x-7)=0 x1=0 x2=7 2) 4m-m²=0 m(4-m)=0 m1=0 m2=4 3) -2y²+3y=0 y(-2y+3)=0 y1=0 y2=1.5 4) x-5x²=0 x(1-5x)=0 x1=0 x2=0.2 5) 0.5x²+1.2x=0 x(0.5x+1.2)=0 x1=0 x2=net reshenija
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| № 24091, Algebra, 8 klase Разложите на множители: 1) ax+2ay-bx-2by | | |
| | ![cybersage](/profiles/upic_4788.jpg)
![cybersage](/images/sch_level_sml_0.gif) cybersage | Ответ см. в файле | | |
| | ![rita](/profiles/upic_5294.jpg)
![rita](/images/sch_level_sml_0.gif) rita | 1) (ax-bx)+(2ay-2by)=x(a-b)+2y(a-b)=(a-b)(x+2y) | | |
| | ![gaika3](/profiles/defined_pic_5.gif)
![gaika3](/images/sch_level_sml_0.gif) gaika3 | a(x+2y)-b(x+2y)=(a-b)(x+2y) | | |
| | ![Katy](/profiles/upic_5285.jpg)
![Katy](/images/sch_level_sml_0.gif) Katy | 1) ax+2ay-bx-2by= x(a-b)+2y(a-b)=(a-b)(x+2y) | | |
| | ![Senja](/profiles/defined_pic_4.gif)
![Senja](/images/sch_level_sml_0.gif) Senja | ax+2ay-bx-2by=a(x+2y)-b(x+2y)=(x+2y)(a-b) | |
| № 24125, Algebra, 8 klase 1) -15√2b+18√2b= 2) 7√11a-19,1√11a= 3) 12,5√3t+0,8√3t= 4) 8√7-√10-7√10= 5)14√3+6√5-7√5-13√3= | | |
| | ![shnee](/profiles/defined_pic_1.gif)
![shnee](/images/sch_level_sml_0.gif) shnee | 1) -15√2b+18√2b= 3√2b 2) 7√11a-19,1√11a= -12,1√11a 3) 12,5√3t+0,8√3t= 13,3√3t 4) 8√7-√10-7√10= 8√7 - 8√10 5)14√3+6√5-7√5-13√3= √3 -√5 | | |
| | ![ЖенюSик](/profiles/defined_pic_2.gif)
![ЖенюSик](/images/sch_level_sml_0.gif) ЖенюSик | 1)3√2b 2)-12√11a 3)13.3√3t 4)8√7-8√10 | | |
| | ![alvita](/profiles/upic_5373.jpg)
![alvita](/images/sch_level_sml_0.gif) alvita | 1) -15√2b+18√2b=3√2b 2) 7√11a-19,1√11a=-12,1√11a 3) 12,5√3t+0,8√3t=13,3√3t 4) 8√7-√10-7√10= 8√7-8√10 5) 14√3+6√5-7√5-13√3=√3 -√5 | | |
| | ![SUPER ANGEL](/profiles/defined_pic_2.gif)
![SUPER ANGEL](/images/sch_level_sml_0.gif) SUPER ANGEL | 1)3≠2b 2)-12.1≠11a 3)13.3≠3t 4)4≠28-4≠40 5)≠3-≠5
| | |
| | ![mednieks](/profiles/defined_pic_1.gif)
![mednieks](/images/sch_level_sml_0.gif) mednieks | 1) -15√2b+18√2b=3√2b 2) 7√11a-19,1√11a=-12,1√11a 3) 12,5√3t+0,8√3t=13,3√3t 4) 8√7-√10-7√10=8√7-8√10 5)14√3+6√5-7√5-13√3=√3-√5 | |
| № 24126, Algebra, 8 klase v Ponideljnik u menja kontroljnaja, po kvadratnim kornjam... ja neponimaju kak rewajutsja primeri tipa : (√3-1)²; ili naprimer: -√180÷√5; √tu³·√t·√u; prowu pomogite, mne nuzno imenno rewenie, kak rewajutsja! zaranie sposibo! | | |
| | ![Mihitos](/profiles/upic_5409.jpg)
![Mihitos](/images/sch_level_sml_0.gif) Mihitos | (√3-1)²=vozvodi v kvadrat_√9-1=vinosi korenj_3-1=2...vot et to4no | | |
| | ![PUMA17](/profiles/defined_pic_2.gif)
![PUMA17](/images/sch_level_sml_0.gif) PUMA17 | Eto lehko u menja uze bila kontrolnaja v ponedelnik ja palucila 9, resenie takoe (√3-1)²= 3-1=2, koren astajotsa takoi kak est a 1 = 1·1=1! a vtaraja zadacka i so lekce , -√180÷√5= -√180÷5=-√36=-6 | | |
| | ![liliana4](/profiles/upic_5378.jpg)
![liliana4](/images/sch_level_sml_0.gif) liliana4 | (√3-1)²= √3+1 -√180÷√5=-√180÷5=-√36=-6 | | |
| | ![colin_jeans](/profiles/upic_5089.jpg)
![colin_jeans](/images/sch_level_sml_0.gif) colin_jeans | ну здесь всё просто (√3-1)²=(раскладываем на множители с помощью формул сокращенного умнаженя)= (√3)²-2√3+1=3-2√3+1=4-2√3...вот и всё -√180÷√5=-√180÷5=√36=6 √tu³·√t·√u=√tu³·√tu=√tu(в четвёртой степени...) | | |
| | ![alvita](/profiles/upic_5373.jpg)
![alvita](/images/sch_level_sml_0.gif) alvita | (√3-1)²=(√3)²-1²=3-1-2 | |
| | № 24141, Algebra, 8 klase 4√3 ÷ 2√3 | | |
| | ![eke](/profiles/upic_5171.jpg)
![eke](/images/sch_level_sml_0.gif) eke | =2√3 | | |
| | ![missL](/profiles/upic_5348.jpg)
![missL](/images/sch_level_sml_0.gif) missL | 1) 4√3 ÷ 2√3 = 2√3 | | |
| | ![victory](/profiles/upic_5322.jpg)
![victory](/images/sch_level_sml_0.gif) victory | 2√3 | | |
| | ![PUMA17](/profiles/defined_pic_2.gif)
![PUMA17](/images/sch_level_sml_0.gif) PUMA17 | 2√3 | | |
| | ![kostja](/profiles/upic_3447.jpg)
![kostja](/images/sch_level_sml_0.gif) kostja | 4√3÷2√3=2√3 | |
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